The specific conductivity of $N/10$ $KCl$ solution at $20 \, ^oC$ is $0.012 \, \Omega^{-1} \, cm^{-1}$ and the resistance of the solution in the cell at $20 \, ^oC$ is $56 \, \Omega$. The cell constant is ........... $cm^{-1}$.

The resistance of a $0.5 \, M$ solution of an electrolyte in a cell was found to be $50 \, \Omega$. If the electrodes in the cell are $2.2 \, cm$ apart and have an area of $4.4 \, cm^2$,then the molar conductivity (in $S \, m^2 \, mol^{-1}$) of the solution is:

What is the conductivity of $0.05 \ M$ $KCl$ solution if cell constant is $1.32 \ cm^{-1}$ and resistance is $528 \ \Omega$?

The resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ M$ $KCl$ solution is $520 \ \Omega$,the molar conductivity of $0.02 \ M$ solution (in $S \ cm^2 \ mol^{-1}$) is (Given: conductivity of $0.1 \ M$ $KCl$ solution $= 1.29 \ S \ m^{-1}$)

Limiting molar conductivity of $CH_3COOH$ (i.e.,$\Lambda^o_{m(CH_3COOH)}$) is equal to:

If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is